added missing parts of the number one
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@@ -121,13 +121,26 @@ Quirin Ecker, k12310122 \\
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\noindent \rule[0.8em]{\textwidth}{0.12mm}\\[-0.5em]
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\noindent \rule[0.8em]{\textwidth}{0.12mm}\\[-0.5em]
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%=======================================================================================
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%=======================================================================================
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\begin{aufgabe}
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\begin{aufgabe}{}
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\begin{enumerate}
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\begin{enumerate}
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\item add back in
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\item figure: \\
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\item add back in
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\includegraphics[width=0.95\textwidth]{fig/aufgabe1_a.png}
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\item add back in
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\item add back in
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\item
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\begin{gather*}
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\Omega_3 = 2 \pi \frac{3.5}{64} \\
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\Omega_4 = \frac{9}{64}
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\end{gather*}
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\item
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\begin{gather*}
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\frac{\Omega_3}{2 \pi} = \frac{3.5}{64} = \frac{7}{128} \\
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N_{0,3} = 128 \\
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\frac{\Omega_4}{2 \pi} = \frac{9}{64 \cdot 2 \pi} = \frac{9}{128 \pi} \\
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\implies \text{Irational because of $\pi$} \\
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\implies \text{Not periodic} \\
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\end{gather*}
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\item (see assignment2\_1.m)
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\item (see assignment2\_1.m)
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\item (see assignment2\_1.m)
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\item table:
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\item table:
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\begin{table}[h]
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\begin{table}[h]
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@@ -146,16 +159,14 @@ Quirin Ecker, k12310122 \\
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\label{tab:energy_power}
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\label{tab:energy_power}
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\end{table}
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\end{table}
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\end{enumerate}
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\end{enumerate}
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\end{aufgabe}
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\end{aufgabe}
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\begin{aufgabe}
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\begin{aufgabe}{}
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\begin{enumerate}
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\begin{enumerate}
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\item $|x[n]| + |h[n]| - 1 = 5 + 4 - 1 = 8$
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\item $|x[n]| + |h[n]| - 1 = 5 + 4 - 1 = 8$
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\item
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\item
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\begin{gather*}
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\begin{gather*}
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A=
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A=
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\begin{bmatrix}
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\begin{bmatrix}
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3 & 0 & 0 & 0\\
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3 & 0 & 0 & 0\\
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@@ -174,8 +185,7 @@ x=
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3\\
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3\\
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4\\
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4\\
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1
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1
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\end{bmatrix}
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\end{bmatrix} \\
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Ax=
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Ax=
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\begin{bmatrix}
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\begin{bmatrix}
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6\\
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6\\
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@@ -189,10 +199,9 @@ Ax=
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\end{bmatrix}
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\end{bmatrix}
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\end{gather*}
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\end{gather*}
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\end{enumerate}
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\end{enumerate}
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\end{aufgabe}
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\end{aufgabe}
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\begin{aufgabe}
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\begin{aufgabe}{}
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\begin{enumerate}
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\begin{enumerate}
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\item $L_y = |x[n]| + |h[n]| - 1 = 50 + 3 - 1 = 52$
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\item $L_y = |x[n]| + |h[n]| - 1 = 50 + 3 - 1 = 52$
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@@ -201,10 +210,9 @@ Ax=
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\item figure: \\
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\item figure: \\
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\includegraphics[width=0.95\textwidth]{fig/aufgabe3_cd.png}
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\includegraphics[width=0.95\textwidth]{fig/aufgabe3_cd.png}
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\end{enumerate}
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\end{enumerate}
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\end{aufgabe}
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\end{aufgabe}
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\begin{aufgabe}
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\begin{aufgabe}{}
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\begin{enumerate}
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\begin{enumerate}
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\item (see assignment2\_4.m)
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\item (see assignment2\_4.m)
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@@ -212,11 +220,10 @@ Ax=
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\includegraphics[width=0.95\textwidth]{fig/aufgabe4_b.png}
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\includegraphics[width=0.95\textwidth]{fig/aufgabe4_b.png}
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\item The magnitued seems to be repeating and the phase response seems to be mirrored accross the x and y axis.
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\item The magnitued seems to be repeating and the phase response seems to be mirrored accross the x and y axis.
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\end{enumerate}
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\end{enumerate}
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\end{aufgabe}
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\end{aufgabe}
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\begin{aufgabe}
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\begin{aufgabe}{}
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\begin{enumerate}
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\begin{enumerate}
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\item (siehe assignment2\_5.m)
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\item (siehe assignment2\_5.m)
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@@ -226,10 +233,6 @@ Ax=
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\item original energy: 41343 \\ reverb energy: 2069.0506 \\ rir energy: $9.9997 \cdot 10^{3}$ \\
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\item original energy: 41343 \\ reverb energy: 2069.0506 \\ rir energy: $9.9997 \cdot 10^{3}$ \\
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explanation: The rir energy is less than one which would explain why the outcoming signal is smaller than the original, because convulution scales proportionally.
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explanation: The rir energy is less than one which would explain why the outcoming signal is smaller than the original, because convulution scales proportionally.
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\end{enumerate}
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\end{enumerate}
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\end{aufgabe}
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\end{aufgabe}
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\end{document}
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\end{document}
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BIN
fig/aufgabe1_a.png
Normal file
BIN
fig/aufgabe1_a.png
Normal file
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